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Start your free trialJennifer Lipps
4,953 PointsWhy am I getting "typeError undefined is not an object" here?
var listItems = document.querySelectorAll('rainbow'); var colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
var listItems = document.querySelectorAll('rainbow');
var colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
<!DOCTYPE html>
<html>
<head>
<title>Rainbow!</title>
</head>
<body>
<ul id="rainbow">
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="js/app.js"></script>
</body>
</html>
2 Answers
Piotr Manczak
Front End Web Development Techdegree Graduate 29,363 Pointsyou could use:
var listItems = document.getElementsByTagName('li');
I checked, it worked. using #rainbow you are targeting <ul> instead of <li>.
Tobiasz Gala
Full Stack JavaScript Techdegree Student 23,529 PointsquerySelector and querySelectorAll is using CSS-like selectors to select elements on the page
document.querySelectorAll('#rainbow li'); // select li elements within id of rainbow
Piotr Manczak
Front End Web Development Techdegree Graduate 29,363 PointsDobre, sam musze poprobowac czy dziala.