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Start your free trialMichael McDonald
2,877 PointsWhy can I not declare my ArrayAdapter as private?
The error I get is "Illegal start of expression". If I remove the 'private' keyword, then my code passes the test.
package com.example;
import android.app.ListActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.ArrayAdapter;
public class MainListActivity extends ListActivity {
public String mSongTitles[] = {"Wah","tjg","kfg"};
@Override
public void onCreate(Bundle savedInstanceState) {
private ArrayAdapter <String> adapter = new ArrayAdapter(this,android.R.layout.simple_list_item_1,mSongTitles);
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main_list);
}
}
Michael McDonald
2,877 PointsWhat is the difference and how do I make the distinction?
Ragnar Sinikas
11,573 PointsAny variable set up inside of a method can't be accessed outside of that method. It's known as a local variable - it's local to the method. But when you declare it outside of the method as public String mSongTitles[] = {"Wah","tjg","kfg"}; then you can make it public, private or protected
Michael McDonald
2,877 PointsThank you very much. That's just the reminder I needed.
1 Answer
Joseph Greene
Courses Plus Student 7,638 PointsIt's all about scope. If you want a variable of any kind to be seen outside it's parent method then it can't be private. This is a good thing. You should always strive for a degree of seperation. To make private variables talk you would use what's called getters and setters. But I think that's out of the scope of the lesson. Once you've got some more android under your belt I recommend taking a full fledged Java course or getting a good book or two. It will make you a better android developer. Keep up the awesome work. You're asking the right kinds of questions to becoming a good programmer.
Ragnar Sinikas
11,573 PointsRagnar Sinikas
11,573 PointsThis ArrayAdapter is in the method, you can declare it as member variable as a private field....