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Start your free trialColin Sandlin
4,512 PointsWhy do you have to create student = students[i]; instead of just using students[i]?
// Instead of this: //
for(var i = 0; i < students.length; i++) {
student = students[i];
message += '<h2>Student: ' + student.name + '</h2>';
message += '<p>Track: ' + student.track + '</p>';
}
// Why doesn't this work the same? //
for(var i = 0; i < students.length; i++) {
message += '<h2>Student: ' + students.name + '</h2>';
message += '<p>Track: ' + students.track + '</p>';
}
2 Answers
Sean T. Unwin
28,690 Points// Why doesn't this work the same? //
for(var i = 0; i < students.length; i++) {
message += '<h2>Student: ' + students.name + '</h2>';
message += '<p>Track: ' + students.track + '</p>';
}
This doesn't work because students
is an Array, which is why we loop through it.
Each item in the Array is a student, so in the first (working) example, we assign the current Array item as student
for easier readability, primarily.
Now, you could do the same without assigning the current iteration of students
to a variable, although in that case we would need to use bracket notation on the Array of the current Index -- the value of i
in the for
loop. This bracket notation is visible in the working example when we assign student
to the current iteration of students
.
In order for your example, which I quoted above, to work we need to add that bracket notation. This would look like the following:
// This will work now //
for(var i = 0; i < students.length; i++) {
message += '<h2>Student: ' + students[i].name + '</h2>'; // <-- Note: the bracket notation
message += '<p>Track: ' + students[i].track + '</p>'; // <-- Note: the bracket notation
}
I hope that helps to clarify.
Colin Sandlin
4,512 PointsAh, yes that makes sense. I appreciate you showing how a tweak to my code could have worked, which in turn clarifies why the instructor did it the other way in his example.