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Start your free trialKohei Ashida
4,882 PointsWhy does jso.name get back 'Kenneth' while jso['language'] raises KeyError: 'language' in javascriptobject.py?
In the following code, I'm confusing in a few things.
class JavaScriptObject(dict):
def __getattribute__(self, item):
try:
return self[item]
except KeyError:
return super().__getattribute__(item)
>>> import javascriptobject
>>> jso = javascriptobject.JavaScriptObject({'name':'Kenneth'})
>>> jso.language = 'Python'
>>> jso.name
'Kenneth'
>>> jso['name']
'Kenneth'
>>> jso['language']
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyError: 'language'
First, why does jso.name get back 'Kenneth' though the key of the value is sting type 'name' in the following lines?
>>> jso = javascriptobject.JavaScriptObject({'name':'Kenneth'})
>>> jso.language = 'Python'
>>> jso.name
'Kenneth'
Second, If the case above works, why does jso['language'] raise KeyError though I've already set jso.language = 'Python' in the following lines?
>>> jso.language = 'Python'
>>> jso.name
'Kenneth'
>>> jso['name']
'Kenneth'
>>> jso['language']
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
KeyError: 'language'
Could someone give me more explanation to these things?
Thanks!
2 Answers
Steven Parker
231,198 PointsRemember that "JavaScriptObject" is a dictionary, but with a customized way of accessing attributes. It looks them up in the dictionary.
So when jso is created, it already has the key 'name' defined. Because of the custom override, "jso.name
" is the same thing as "jso.['name']
" which returns the value from the dictionary.
But "jso.language = 'Python'
" does not add a value to the dictionary., so you get an error when you try to access it.
However, if you do "jso['language'] = 'Python'
" instead, it will be added to the dictionary, and you can get it back.
Kohei Ashida
4,882 PointsThanks for your explanation!
So when jso is created, it already has the key 'name' defined. Because of the custom override, "jso.name" is the same thing as "jso.['name']" which returns the value from the dictionary.
This makes me clear to understand what is going on here.
Thanks a lot!
Timothy Mattingly
15,934 PointsTimothy Mattingly
15,934 PointsIn the video, jso.language does return 'python'
Steven Parker
231,198 PointsSteven Parker
231,198 PointsYes, "
jso.language
" returns the property directly. But "jso['language']
" would not.