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9,884 PointsWhy does my if loop not remove the list of numbers inside messy_list?
I thought that using "if type(item) is not int" would remove the list of numbers within messy_list.
I tried testing type([1, 2, 3]) in the REPL and it tells me that the class is 'list'.
I don't see why my loop would not remove the list then. Can anyone help me with this?
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
messy_list.insert(0, messy_list.pop(3))
# Loop through each item in messy_list
for item in messy_list:
if type(item) is not int:
messy_list.remove(item)
1 Answer
Dave StSomeWhere
19,870 PointsIt is because you are modifying the same list you are iterating over. When you do a remove, you change that list index and the next time through the loop it will skip an entry.
First time through the list your index is 0 and you check the letter "a". Then you remove the letter a. Next time through the list you inspect index 1 which is now 3 (not 2 as expected - which isn't really noticed since 2 doesn't get removed anyway). Now when you get to False
and remove it, you'll skip that final nested list.
You need to loop a copy of the list.
ps18
9,884 Pointsps18
9,884 PointsThank you for the help!