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Start your free trialWinston Quin
10,359 PointsWhy does the correct answer include an "=" sign? I never saw this in the video.
I worked out the answer with experimentation, but never found at which point in the preceding videos this was mentioned. I'm having trouble on the next challenge, and think an explanation might help me.
so this is correct:
def mod(a, b) puts = a % b end
and this is not:
def mod(a, b) puts a % b end
but I don't understand why
def mod(a, b)
puts = a % b
end
3 Answers
Jennifer Nordell
Treehouse TeacherHi there! To be honest, I'm not sure why your code passed other than to say that every Ruby block returns a value. However, the challenge never asked you to print anything. It asked you to return a value. At 0:38 of the preceding video the return
statement is first used. It is, of course, entirely different than the puts
statement.
The answer it was expecting (I believe) was:
def mod(a, b)
return a % b
end
I know that it has something to do with "implicit return" values in Ruby, but I'm far from an expert. I do know that because every Ruby block returns a value, it would seem to me that the result in your second variant is assigned to puts which results in the correct value being returned while the puts a % b
probably results in an object being returned.
Hope this helps!
Martin Zarate
10,723 PointsTechnically all you need is:
def mod(a, b)
a % b
end
Remember the return is implied, and it is asking to "return" not to print, so you do not need the "put" keyword, you could use the "return" keyword instead. Cheers.
glasscheck
7,302 Points= is an assignment operator
so you have assigned a variable called puts to the value of a % b