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Ruby Ruby Operators and Control Structures Logical Operators Practice time! Operators and Control Structures

Posted by Ron L
Ron L
6,463 Points

Why does the if statement 'if divisible_by_3?(number)' come after calling the methods?

Here is the code: name = get_name() greet(name) number = get_number()

if divisible_by_3?(number) puts "Your number #{number} is divisible by 3" else puts "Sorry, your number #{number} is not divisible by 3." end

We're using the if statement on divisible_by_3? method with the number parameter, which was returned in the defined method above it, so I don't see why we can't place the if divisible_by_3? statement before calling the methods, like all the other parts of the code.

And, what is the intuitive part that would tell us that this portion needs to come after the calling of the methods?

2 Answers

Michael Prince
Michael Prince
23,132 Points
Michael Prince
Michael Prince
23,132 Points

Ron,

It looks like this has to come after the methods because the get_number() method is converting the answer to an integer (to_i). Once the answer is an integer you can then perform the divisible_by_3? method.

Jeramae Bohol
Jeramae Bohol
4,550 Points
Jeramae Bohol
Jeramae Bohol
4,550 Points

Ron,

I hope this other version helps you. It works the same way as the video but easier to understand.

def get_name()
  print "Enter your name: "
  return gets.chomp
end

def greet(name)
  puts "Hi #{name}!"
  if (name == "Jason")
    puts "That's a great name!"
  end
end

def get_number()
  print "What number would you like to test? "
  return gets.chomp.to_i
end

def divisible_by_3?(number)
  if (number % 3 == 0)
    puts "You number is divisible by 3!"
  else
    puts "Your number is not cleanly divisible by 3!"
  end
end

name = get_name()
greet(name)
number = get_number()
divisible_by_3?(number)