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10,271 Pointswhy does this code not work?
function printD(html) {
return document.write(html);
};
var alphabetsZ = ["A", "B", "C"];
function olArr(liArr) {
var listz = "<ol>";
for (var i = 0; i < liArr.length; i += 1) {
listz += "<li>" + liArr[i] + "</li>";
};
listz += "</ol>";
};
printD( olArr( alphabetsZ ) );
// output - undefined
i know the code is fine in general and if i put printD(listz); within the function and call the function as normal it will work fine. but trying a different way that i did, to me my way should work too. i know the problem is mainly :
printD( olArr( alphabetsZ ) );
it comes off as undefined even though the code looks fine to me too! my guess is you cannot use function within a function?
1 Answer
Elijah Quesada
Front End Web Development Techdegree Graduate 32,965 PointsYou need to add a return statement. A function will return undefined by default. In order to return a value you need to add the return statement.
function printD(html) {
return document.write(html);
};
var alphabetsZ = ["A", "B", "C"];
function olArr(liArr) {
var listz = "<ol>";
for (var i = 0; i < liArr.length; i += 1) {
listz += "<li>" + liArr[i] + "</li>";
};
return listz += "</ol>";
};
printD( olArr( alphabetsZ ) );
mk37
10,271 Pointsmk37
10,271 Pointsomg i feel so stupid that i forgot to add a return. thanks for the help Elijah