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Python Comparison Challenge

Posted by Audrey Zzzz
Audrey Zzzz
760 Points

Why does this code result in 3 being called neither a fizzy nor a buzzy number?

is_fizz = number % 3 == 0

is_buzz = number % 5 == 0

if is_fizz == 0 and not is_buzz:

print ("is a Fizz number.")

1 Answer

Steven Parker
Steven Parker
231,275 Points
Steven Parker
Steven Parker
231,275 Points

Some of the code appears to be missing, but assuming "number" begins as 3, then:
is_fizz = number % 3 == 0 :point_left: this will assign "is_fizz as True, and
is_buzz = number % 5 == 0 :point_left: this will assign "is_buzz as False, then
if is_fizz == 0 and not is_buzz: :point_left: since True is not equal to 0, this test will fail.

While the result of comparing booleans to numeric values is reliable, it can result in confusing code. It's much better to test booleans directly (or inverted with "not", as you did with is_buzz). So a fix (and a better test) here would be:

if is_fizz and not is_buzz:
    print ("is a Fizz number.")

For future questions, take a look at this video about sharing a snapshot of your workspace. That lets you share your entire code (including multiple files) just by posting a link. And when you do post code directly, take a look at this one about using Markdown formatting to preserve the code's appearance.