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JavaScript AJAX Basics (retiring) AJAX and APIs Displaying the Photos

Jess Hines
Jess Hines
5,411 Points
Posted by Jess Hines
Jess Hines
5,411 Points

Why doesn't $.ajax() work on this challenge?

Just to explore, I tried to do this challenge using the more-flexible $.ajax() method, but I get a CORS-related error:

XMLHttpRequest cannot load http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?&tags=Dog&format=json. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://port-80-ff9i6ym5pp.treehouse-app.com' is therefore not allowed access.

But if I use $.getJSON() it works as in the video

//this throws the error
    $.ajax({
      url: flickrUrl, 
      data: flickrOptions,
      success: flickrSuccess
    });
//this returns the data as per the video
    $.getJSON(flickrUrl, flickrOptions, flickrSuccess);

1 Answer

LaVaughn Haynes
LaVaughn Haynes
12,397 Points
LaVaughn Haynes
LaVaughn Haynes
12,397 Points

My guess is that you probably just need to specify jsonp in your ajax settings object sing you are requesting data from a different server than the one your script is on

dataType: "jsonp"

like this

$(document).ready(function() {

 var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";

 $('form').submit(function (evt) {
    var $submitButton = $('#submit');
    var $searchField = $('#search');
    evt.preventDefault();
    $searchField.prop("disabled",true);
    $submitButton.attr("disabled", true).val("searching....");
    var animal = $searchField.val();
    $('#photos').html('');

    function flickrSuccess(data){
      var photoHTML = '';
      if (data.items.length > 0) {
        $.each(data.items,function(i,photo) {
          photoHTML += '<li class="grid-25 tablet-grid-50">';
          photoHTML += '<a href="' + photo.link + '" class="image">';
          photoHTML += '<img src="' + photo.media.m + '"></a></li>';
        }); // end each
      } else {
        photoHTML = "<p>No photos found that match: " + animal + ".</p>"
      }
      $('#photos').html(photoHTML);
      $searchField.prop("disabled", false);
      $submitButton.attr("disabled", false).val("Search");
    }

    flickrOptions = {
      tags: animal,
      format: "json"
    };

    $.ajax({
      url: flickerAPI, 
      data: flickrOptions,
      dataType: "jsonp",
      success: flickrSuccess
    });
    // end ajax

  }); // end click

}); // end ready
Jess Hines
Jess Hines
5,411 Points
Jess Hines
Jess Hines
5,411 Points

That was it! I didn't think I needed that because of the jsoncallback=? part of the query, but I did need to add dataType: 'jsonp'. Thanks!