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Start your free trialMatt Sturdivant
890 PointsWhy doesn't my function pass the coding challenge? Its output is the same as the example.
E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
{'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
Lowercase the string to make it easier.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
string = string.lower()
string_list1 = string.split(" ")
string_list2 = string_list1[:]
string_dictionary = {}
for item1 in string_list1:
counter = 0
index = 0
for item2 in string_list2:
if item2 == item1:
counter += 1
string_list2.pop(index)
index +=1
if counter > 0:
string_dictionary[item1] = counter
return string_dictionary
1 Answer
Steven Parker
231,275 PointsThe error message you get contains this hint: "Be sure you're lowercasing the string and splitting on all whitespace!"
For a "split" to work on "all whitespace", the argument should be left empty. Providing a space argument causes it split specifically (and only) on every space.
Also, it's not clear why you would "pop" anything from the second list, since by doing so you would be likely to get an inaccurate count when you encounter a repeated word again in the outer loop.