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Joshua Gressman
4,695 PointsWhy doesn't the $isbn = $key variable working?
<?php foreach($books as $key => $book) { ?> <?php $isbn = $key; ?> <li><?php echo $book; ?></li> <?php } ?>
<?php
$books["978-0743261690"] = "Gilgamesh";
$books["978-0060931957"] = "The Odyssey";
$books["978-0192840509"] = "Aesop's Fables";
$books["978-0520227040"] = "Mahabharta";
$books["978-0393320978"] = "Beowulf";
?><html>
<head>
<title>Five Great Books</title>
</head>
<body>
<h1>Five Great Books</h1>
<ul>
<?php foreach($books as $key => $book) { ?>
<?php $isbn = $key; ?>
<li><?php echo $book; ?></li>
<?php } ?>
</ul>
</body>
</html>
1 Answer
Daniel Stopka
13,520 PointsHi Joshua,
actually it is working, but probable not how you wanted... By $isbn = $key; you have assigned key to variable, but didn't echo out... So your code can be changed - instead of using $key in foreach, you can use $isbn (it is variable name, where keys from books array will be added), so it will make more sense in your code and then you can echo $isbn where you want...
<?php foreach($books as $isbn => $book) { ?>
<li><?php echo $isbn . ' - ' . $book; ?></li>
<?php } ?>
Andrew Dovganyuk
10,633 PointsAndrew Dovganyuk
10,633 PointsThank you Daniel! It work & was helpfull!!!