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Start your free trialMahmoud Altair
1,509 PointsWhy getting a 'Bummer'?!
If I did exactly what's required and tested my code.. why am I still getting a 'Bummer'?!
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
string = string.lower()
words = string.split(' ')
unique_words = []
for word in words:
if word not in unique_words:
unique_words.append(word)
counters = []
for unique_word in unique_words:
counter = 0
while unique_word in words:
words.pop(words.index(unique_word))
counter += 1
counters.append(counter)
return dict(zip(unique_words, counters))
word_count("I do not like it Sam I Am")
1 Answer
KRIS NIKOLAISEN
54,972 PointsYou need to split on all whitespace. This is done by leaving out the argument for the split method
words = string.split()
Mahmoud Altair
1,509 PointsMahmoud Altair
1,509 PointsThanks for quick response.. I replaced "words = string.split(' ')" with "words = string.split()" still getting a bummer!
Mahmoud Altair
1,509 PointsMahmoud Altair
1,509 PointsBummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!