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JavaScript JavaScript Basics (Retired) Working With Numbers Numbers and Strings

Josh Puckett
Josh Puckett
2,787 Points

Why is it parseInt(stringVar) and not stringVar.parseInt

Yes I know it doesn't work but what is the technical reason? It seems like it would be a useful string method...

1 Answer

Steven Parker
Steven Parker
231,007 Points

That's a cute idea.

I don't know why parseInt was not implemented as a string method. Maybe because it takes one more character to call it that way?

But you can always make it so yourself:

String.prototype.parseInt = function () { return parseInt(this); }

Remember to use parentheses when calling it: "stringVar.parseInt()"

Josh Puckett
Josh Puckett
2,787 Points

ty, the only reason I could think of was it was a legacy thing