Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points
Posted by Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points

Why is my $.getJSON not working?

For the code challenge, the url and data are stored in variables.I stored the callback function in a variable also. Now I just put these variables as arguments to $.getJSON() and I get an error saying I need to use the $.getJSON() storing the arguments in proper order. I'm lost.

weather.js 
$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  var response= function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }

  $.getJSON(weatherAPI, data, response);

});
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

2 Answers

Moses Wynn
Moses Wynn
20,461 Points
Moses Wynn
Moses Wynn
20,461 Points

Try this:

$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';

  var data = {
    q : "Portland,OR",
    units : "metric"
  };

  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  }

  $.getJSON(weatherAPI, data, showWeather);

});

The response will be invalid because openweathermap requires an API key now. But it will get you through the quiz.

hamdi taboubi
hamdi taboubi
3,627 Points
hamdi taboubi
hamdi taboubi
3,627 Points

remove $.getJSON(weatherAPI, data, response);