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Zhihao Wang
9,687 PointsWhy is my open request code wrong?
It asks to open a request with the get method, then directing it to "footer.html"
How is this code wrong?
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
};
request.open('GET', 'footer.html');
};
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
2 Answers
Robert Richey
Courses Plus Student 16,352 PointsHi Zhihao,
The request.open() method needs to be outside of the callback function, like this:
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
request.open('GET', 'footer.html');
Mike Burnett
8,429 PointsDon't feel bad, Zhihao. I made the exact same mistake. And thanks, Robert! :)
Zhihao Wang
9,687 PointsZhihao Wang
9,687 PointsHey Robert,
Wow I can't believed I overlooked that! Such an amateur mistake :D!
Thanks, and Happy Thanksgiving!