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Daniel Maia
6,228 PointsWhy is this not passing the challenge?
Why is this not passing the challenge?
It works on Pycharm but it wont pass the challenge.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
my_string = string.lower().split()
my_dict = {}
for item in my_string:
if item in my_dict:
my_dict[item] += 1
else:
my_dict[item] = 1
print(my_dict)
1 Answer
Steven Parker
230,995 PointsOne of the challenge requirements is: "The function needs to return a dictionary."
But the code shown here doesn't return anything at all.
Also, for the challenge, you won't need to "print" anything.