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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by youssef moustahib
youssef moustahib
2,303 Points

Why isn't this passing?

Alright, this one might be a bit challenging but you've been doing great so far, so I'm sure you can manage it. I need you to make a function named word_count. It should accept a single argument which will be a string. The function needs to return a dictionary. The keys in the dictionary will be each of the words in the string, lowercased. The values will be how many times that particular word appears in the string. Check the comments below for an example.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(astring):
    dic = {}
    astring.lower()
    newstring = astring.split()
    for word in newstring:
        dic[word] = newstring.count(word)

    return dic

1 Answer

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

your code is ok but the words in your dictionary are not lower-case like the challenge asks. you are calling the lower method, but you are not reassigning the return either to the parameter or another variable, so the words in the string are not being lowered before hitting the rest of the code. simply reassign the return of lower to the parameter and it will pass.

youssef moustahib
youssef moustahib
2,303 Points

Hi James,

I don't understand your answer. Could you provide your code so I can see? Thanks