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Start your free trialDan Avramescu
11,286 PointsWhy isset and empty in 2 different statements?
Wouldn't be better if this code
if (isset($_GET['pg'])) {
$current_page = filter_input(INPUT_GET,'pg',FILTER_SANITIZE_NUMBER_INT);
}
if (empty($_GET['pg'])) {
$current_page = 1;
}
was written like
if (!empty($_GET['pg'])) {
$current_page = filter_input(INPUT_GET,'pg',FILTER_SANITIZE_NUMBER_INT);
}else{
$current_page = 1;
}
isset($_ GET['pg']) returns true even if the query wil be ?pg=0, while empty checks for 0, '0' ( the latter doesn't matter here since we use SANITIZE _ NUMBER _ INT). Ah, actually after reading the docs, i see the FILTER_SANITIZE_NUMBER_INT returns the number as a string :) Still, this question stands.
1 Answer
Jason Anello
Courses Plus Student 94,610 PointsHi Dan,
The second if condition was supposed to be if (empty($current_page)) {
The idea here is that you first check if it's set and sanitize it by removing non-numeric characters.
The second if
is to make sure you didn't get back an empty string or "0".
With your rewritten code, it's not going to work when the 'pg' variable is non-numeric. Example: ?pg=abc
Your if condition will be true because it's not empty and then $current_page will be set to an empty string once the letters are stripped out of it.