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Andrey Misikhin
16,529 PointsWhy it doesn't work?
I'm tried different variants. Its works in console on my PC, but here the bummer appers.
First:
def word_count(string): dic = {} arr = string.lower() arr = arr.split(" ") counter = 1 while len(arr) > 0: item = arr.pop(0) while item in arr: item = arr.pop(arr.index(item)) counter += 1 else: dic[item] = counter counter = 1 return dic
Second:
def word_count(string): dic = {} arr = string.lower() arr = arr.split(" ") for item in arr: dic[item] = arr.count(item) return dic
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
dic = {}
arr = string.lower()
arr = arr.split(" ")
counter = 1
while len(arr) > 0:
item = arr.pop(0)
while item in arr:
item = arr.pop(arr.index(item))
counter += 1
else:
dic[item] = counter
counter = 1
return dic
2 Answers
James Reinhold
12,361 Pointsdef word_count(string):
string = string.lower()
word_dict = {}
word_list = string.split()
for sel_word in word_list:
count = 0
for word in word_list:
if sel_word == word:
count +=1
word_dict[sel_word] = count
return word_dict
The difference is that .split(" ") splits only on spaces and .split() splits on all whitespace. Whitespace includes spaces, tabs, newlines, vertical spaces, etc.
The challenge expects you to split on all whitespace
Andrey Misikhin
16,529 PointsThank you, James! Now understood the meaning of words "all whitespace" :)