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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Posted by Ja'Nel Johnson
Ja'Nel Johnson
10,314 Points

Why won't it accept my answer?

Challenge: Use a DOM element's innerHTML property to set the HTML inside the sidebar div to the server's response code challenge?

The error message keeps telling me to insert code that is already there.

I'm so confused.

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4 && xhr.status === 200) {
    document.getElementById('sidebar').innerHTML=xhr.response.Text;
  }
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Hi Ja'Nel

You pretty much have it, but you put a period between 'response' and 'Text.' It is just one word - 'responseText' Once that's fixed, you're all good. :)

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4 && xhr.status === 200) {
    document.getElementById('sidebar').innerHTML=xhr.responseText; //removed period
  }
};

Jason