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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Genius Chamisa
Genius Chamisa
6,620 Points

word count challenge

where am i going wrong

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    string="team treehouse is here"
    dictionary={}
    dicti=string.lower().split()
    for items in dicti:
        value=dicti.count(items)
        dictionary[items]=value
    return dictionary

1 Answer

Robert Stewart
Robert Stewart
11,921 Points
Robert Stewart
Robert Stewart
11,921 Points

Well, the one thing I notice is that you're immediately overriding whatever value is passed through as string.

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string): #<= String is passed in here.
    string="team treehouse is here" #<= You override it here.
    dictionary={}
    dicti=string.lower().split()
    for items in dicti:
        value=dicti.count(items)
        dictionary[items]=value
    return dictionary

Whatever is calling the code is expecting the answer to be based on the string it passed to the function in the first place. You're returning a completely different result.