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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Kairos F
Kairos F
19,925 Points

Word Count Challenge. Can't get this to pass....

This keeps failing on me, telling me not to split on a space... the function works perfectly in workspaces... Can't get it to pass in the code challenge though.

All help appreciated. Thanks,

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):

    dictionary = {}
    #take the sting and split it into words and put them in a list
    string = string.lower()
    string = string.replace(", " , " ")
    string = string.replace(".", " ")
    string_list = string.split(" ")

    for word in string_list:
        if word not in dictionary:
            dictionary[word] = 1
        else:
            dictionary[word] += 1

        return dictionary

1 Answer

Andrew Voitsekhovskyy
Andrew Voitsekhovskyy
3,523 Points
Andrew Voitsekhovskyy
Andrew Voitsekhovskyy
3,523 Points

Hi, you have good code but one silly mistake ..... put "return" in for loop)

for word in string_list:
        if word not in dictionary:
            dictionary[word] = 1
        else:
            dictionary[word] += 1
return dictionary

and use split for everything 

string.split()
Kairos F
Kairos F
19,925 Points

Thanks Andrew, fixed that, but it's still not passing....