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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Christopher Grant
Christopher Grant
2,288 Points

wordcount

I have tested my code and everything seems to work fine, I get back a dictionary with the words in lower case with a key value of the correct number of times the word appears in the sentence but the test still says it's incorrect.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(input):
    input_split = list(input.split(" "))
    results = {}
    for x in range(len(input_split)):
        count = 0
        for y in range(len(input_split)):
            if input_split[x].lower() == input_split[y].lower():
                count += 1
        results[input_split[x].lower()] = count
    return results

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

You are very close! The challenge is looking for the input to be split on whitespace instead of a literal space. To split on whitespace is the default for split()

Christopher Grant
Christopher Grant
2,288 Points

lol, yep. I removed the " " from split and it worked just fine. Was driving me nuts I tested like a 100 times. Thanks :)