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X TAO-COLLINS
4,922 Pointsword_count
def word_count(str): return dict(Counter(str.lower().split()))
word_count("I do not like it Sam I Am") {'i': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'sam': 1, 'am': 1}
I have successfully ran through this in Python 3.6.1 Shell.
It gives the correct answer as required, I don't understand what's wrong? Help needed ASAP
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
from collection import Counter
def word_count(str):
return dict(Counter(str.lower().split()))
word_count("I do not like it Sam I Am")
X TAO-COLLINS
4,922 PointsI have changed the str into string, still not working. :(
2 Answers
X TAO-COLLINS
4,922 PointsI have tried a different method, less straight-forward than the previous one I posted above. I took the reference from https://www.pythonlearn.com/html-008/cfbook010.html
def word_count(str): d=dict() for x in str.lower().split(): if x not in d: d[x]=1 else: d[x]=d[x]+1 return d
word_count("I do not like it Sam I Am") {'i': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'sam': 1, 'am': 1}
kjoseph
2,704 PointsI copied the code you posted originally and replaced str with string and it worked for me! Try closing and reopening your window?
X TAO-COLLINS
4,922 PointsThanks
kjoseph
2,704 Pointskjoseph
2,704 PointsNew idea: try changing str to string.