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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Guntas Singh
Guntas Singh
2,107 Points

wordcount

can't solve

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    string_list=string.split()

    for item.lower() in string_list:

1 Answer

Nazim Mohamed
Nazim Mohamed
1,014 Points

I would lowercase the string before the loop, then within the loop you just need to

print(len(item))