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Jaya Verma
1,397 Pointswordcount
this code works fine in workspace Does the order of dictionary keys matter?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(s):
word_list=list(s.lower().split(' '))
word_dict={}
for w in word_list:
if w in word_dict:
word_dict[w]+=1
else:
word_dict[w]=1
return word_dict
