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Leo Marco Corpuz
18,975 Pointsword_count challenge update
Here's my code updated. I can't figure out what's wrong.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(phrase):
phrase=phrase.lower()
phrase=phrase.split(" ")
dict_phrase={}
for word in phrase:
if word in dict_phrase:
continue
else:
value_count= phrase.count(word)
dict_phrase[word]=value_count
return dict_phrase
1 Answer
Steven Parker
230,995 PointsThe error message contains a hint: "
To split on "all whitespace" the "split" function should be given no argument. Giving it a space causes it to split on individual spaces and not combine them or consider other whitespace characters.
Happy coding! 
