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David Luo
1,215 Pointsword_count: code works on my IDE, but having error. I know it's something small somewhere but can't seem to debug this!
Well, I found a few ways to approach this that I thought would have worked, but unfortunately getting an error. This code works for the test case on my IDE, but can't seem to pass this on the Treehouse workspace.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(str):
words_list = str.lower().split(" ")
# defaulting dictionary with corresponding words as keys and 0 for values
# d = dict(zip(words_list,[0]*len(words_list)))
d = dict.fromkeys(words_list, 0)
# iterate and count
for word in words_list:
d[word] += 1
return d
2 Answers
andren
28,558 PointsThe problem is that the challenge wants you to split on all whitespace. You are currently splitting on single spaces, and while that is an example of whitespace it is far from all. Multiple spaces, line-breaks, tabs and so on are also examples of whitespace, which won't get split based on your code.
Luckily the solution is actually quite simple. The split method splits on all whitespace by default if you don't provide it with an argument. So the solution to this issue is to simply remove the argument you pass it. Like this:
def word_count(str):
words_list = str.lower().split()
# defaulting dictionary with corresponding words as keys and 0 for values
# d = dict(zip(words_list,[0]*len(words_list)))
d = dict.fromkeys(words_list, 0)
# iterate and count
for word in words_list:
d[word] += 1
return d
David Luo
1,215 PointsAndren, thanks again. so many subtle points to consider!