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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Anshu Aradhyula
Anshu Aradhyula
4,317 Points

wordcount.py My correct code is giving different output.

I wrote code that correctly returns the output. But it is wrong on tree house. It looks like my words are outputted in a different order. Maybe treehouse tester checks for the same order?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string = string.lower()
    list_of_words = string.split(" ")
    dictionary = {}
    for current_word in list_of_words:
        count = 0
        for iterated_word in list_of_words:
            if current_word == iterated_word:
                count += 1
        dictionary.update({current_word : count})
    return dictionary

1 Answer

Anshu Aradhyula
Anshu Aradhyula
4,317 Points
Anshu Aradhyula
Anshu Aradhyula
4,317 Points

Solved. It seems teamtreehouse is picky with how the word gets splitted since there's different kinds of whitespace. By replacing string.split(" ") with string.split() I was able to pass.