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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Rakshit H Ravishankar
Rakshit H Ravishankar
1,309 Points
Posted by Rakshit H Ravishankar
Rakshit H Ravishankar
1,309 Points

wordcount.py not working

def word_count(my_list): d={} for char in re.split('\s', my_list.lower()) if char in d: d[char] += 1 else: d[char] = 1 return d

this code is not working. Please point out the error.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(my_list):
    d={}
    for char in re.split('\s', my_list.lower())
        if char in d:
            d[char] += 1
        else:
            d[char] = 1
    return d

1 Answer

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

Hi Rakshit, you're just missing the colon from the end of for line. I would recommending naming your variables to something more intuitive, as my_list is actually a string, and char is actually a word.. but it's not required to complete this challenge.

import re

def word_count(my_list):
    d={}
    for char in re.split('\s', my_list.lower()):  # colon here
        if char in d:
            d[char] += 1
        else:
            d[char] = 1
    return d