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Python Python Collections (Retired) Dictionaries Word Count

Posted by Thomas Katalenas
Thomas Katalenas
11,033 Points

word_dict 

def word_count(arg)
    word_dict = {}
    word_dict[arg] = count 
    if arg in dict:
      count += 1

# my code is starting to confuse me now!!

edited by mod

2 Answers

Andreas cormack
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.a{fill-rule:evenodd;}techdegree seal-36
Andreas cormack
Python Web Development Techdegree Graduate 33,011 Points
Andreas cormack
.a{fill-rule:evenodd;}techdegree seal-36
Andreas cormack
Python Web Development Techdegree Graduate 33,011 Points

Hi Thomas

Welcome to Treehouse.

def word_count(arg)
    word_dict = {}
    word_dict[arg] = count # not sure what is this count meant to represent 
    if arg in dict: # here your checking if the entire string is in the dictionary rather than each word
      count += 1

# see below my code

def word_count(arg):
  word_dict = {}
  words  = arg.split() # split the string into individual words
  for word in words:  # iterate through the list
    if word in word_dict: # if the word is already in the dictionary add 1 to the value
      word_dict[word]= word_dict[word] + 1
    else:
      word_dict[word]=1
  return word_dict

happy coding

Thomas Katalenas
Thomas Katalenas
11,033 Points
Thomas Katalenas
Thomas Katalenas
11,033 Points

Some where in the dark trenches of my brain a dim light started to stir.