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Start your free trialNthulane Makgato
Courses Plus Student 19,602 PointsWrapping up the website task 5/7
If there ever was a code challenge that rubbed me up the wrong way, this would be it. here is the question:
"PalprimeChecker objects have a method called isPalprime(). This method does not receive any arguments. It returns true if the number property contains a palprime, and it returns false if the number property does not contain a palprime. (Tip: 17 is not a palprime.) Turn the second echo statement into a conditional that displays “is” or “is not” appropriately. The conditional should call the isPalprime method of the $checker object. If the isPalprime method returns true, then echo “is”; otherwise, echo “is not”."
require_once("class.palprimechecker.php");
$checker = new PalprimeChecker();
$checker -> number = 17;
echo "The number " . $number;
if($checker-> isPalprime()) {
echo "is ";
} else {
echo "is not ";
} else {
echo "a palprime. ";
}
This is my best effort yet it doesn't pass.
What I want to know is how can "isPalprime" not receive arguments yet check if a number is a palprime?
how is "isPalprime" checking if $checker is a prime through "($checker->isPalprime)" because it looks like $checker is assigning a property.
How does "isPalprime" extract 17 from $checker since $number is just a property of the object $checker.
Any help would be appreciated.
1 Answer
Coco Jackowski
12,914 Points1) That "->
" lets you get or set object properties just like any other variable, but it also lets you call methods, so $checker->isPalprime()
is calling the isPalprime()
method of $checker
.
2) The isPalprime()
method is a method of the object $checker
, and is therefore able to 'see' the value of number
, which is just another property of $checker
Maybe there is more to your code, but this line
echo "The number " . $number;
seems to include a variable that has no value and was never initialized.