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Mona Jalal
4,302 Pointszip doesn't work
why the following doesn't work?
def combo(iter1, iter2): return zip(iter1, iter2)
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(iter1, iter2):
return zip(iter1, iter2)
2 Answers
crosscheckking
20,110 PointsThe only thing that you are missing is that you will need to make it into a list. Other than that you are good.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(iter1, iter2):
return list(zip(iter1, iter2))
crosscheckking
20,110 PointsHere is another way you could do it. This way doesn't use zip. Instead it just appends to a list.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(iter1, iter2):
return_list = []
for item in range(len(iter1)):
return_list.append((iter1[item], iter2[item]))
return return_list