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Start your free trialMahmoud Nabil
1,495 Pointsbackground-image: linear-gradient (to top, steelblue, 90deg, darkslateblue);
is that true?
/* Complete the challenge by writing CSS below */
.main-header {
background-image: linear-gradient (to top, steelblue, 90deg, darkslateblue);
}
<!DOCTYPE html>
<html>
<head>
<title>Lake Tahoe</title>
<link rel="stylesheet" href="page.css">
<link rel="stylesheet" href="style.css">
</head>
<body>
<header id="top" class="main-header">
<span class="title">Journey Through the Sierra Nevada Mountains</span>
<h1 class="main-heading">Lake Tahoe, California</h1>
</header>
<div class="primary-content">
<p class="intro">
Lake Tahoe is one of the most breathtaking attractions located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
</p>
<a class="callout" href="#more">Find out more</a>
</div><!-- End .primary-content -->
</body>
</html>
3 Answers
Mahmoud Nabil
1,495 PointsThanks to you all .. The answer is (to top, color1, color2 90%);
Jochen Landua
9,416 PointsThe syntax is: "background: linear-gradient(direction, color-stop1, color-stop2, ...);" I think your 90deg in the middle of the colors could make some trouble ... 90deg is a direction. You can start (90deg, color1, color2)
Hope you understand my rusty english ...
Mahmoud Nabil
1,495 PointsMany thanks but it not work
Jochen Landua
9,416 PointsOk, we shouldn't post the solutions in the forum, so i try it again with a hint.
You are on a good way, the syntax should look like this:
background-image: linear-gradient (direction, color1 | stop1, color2 | stop2);