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Python Practice Creating and Using Functions in Python Practice Functions Use an External Function

CESAR AGUILAR
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CESAR AGUILAR
Python Development Techdegree Student 710 Points
Posted by CESAR AGUILAR
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CESAR AGUILAR
Python Development Techdegree Student 710 Points

not sure what does TypeError: object of type 'type' has no len() mean?

using_a_function.py 
"""
This is importing a function named `tweet` from a file
    that we unfortunately don't have access to change.

You use it like so:
>>> tweet("Hello this is my tweet")

If the function cannot connect to Twitter,
    the function will raise a `CommunicationError`
If the message is too long,
    the function will raise a `MessageTooLongError`
"""
from twitter import (
    tweet,
    MessageTooLongError,
    CommunicationError,
)


message = input("What would you like to tweet?  ")
tweet(message)

from twitter import(tweet)
try:
    tweet = len(CommunicationError)
except CommunicationError:
    print("An error occurred attempting to connect to Twitter. Please try again!")
try:
    tweet = len(CommunicationError)
except CommunicationError:
    print("An error occurred attempting to connect to Twitter. Please try again!")
Francesco Gambardella
Francesco Gambardella
2,094 Points

I got AssertionError: False is not true. Make sure you catch the CommunicationError in a try except block.

1 Answer

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
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Jennifer Nordell
Treehouse Teacher

Hi there, CESAR AGUILAR! The CommunicationError is in itself a class. It is not iterable so the len() function won't work on it.

You're really close here. Your tweet(message) was meant to be put inside the try as it is the thing that could potentially fail. Imagine that you're about to send a tweet when your phone loses connection to the network. That might create a communication error with the server.

try:
    tweet(message)  # try to twee the message
except CommunicationError:  # this fires if there was a communication error with the server
    print("An error occurred attempting to connect to Twitter. Please try again!")

Hope this helps! :sparkles: