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Java Java Basics Perfecting the Prototype String Equality

Posted by Unsubscribed User
Unsubscribed User
7,386 Points

Add an if statement that checks to see if firstExample is equal to secondExample. If it is, print out "first is equal to

I tried typing "hello" the first time but that didn't work either. Help please.

Equality.java 
// I have imported a java.io.Console for you, itis named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equalsIgnoreCase ("secondExample")) {
  console.printf("first is equal to second. \n");
  system.exit(0);
}

4 Answers

Ethan M
Ethan M
10,637 Points
Ethan M
Ethan M
10,637 Points

The conditional statement is expecting firstExample to equal literally "secondExample" you set the variable in a set of strings therefore it'll be expecting that. FIx

// I have imported a java.io.Console for you, itis named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equalsIgnoreCase (secondExample)) {
  console.printf("first is equal to second. \n");
  system.exit(0);
}

If you have no strings in the parentheses then it will know that your talking about the string secondExample as opposed to literally expecting secondExample as the value of firstExample.

To be specific if you didn't have the set of strings on secondExample it will now replace secondExample with 

if (firstExample.equalsIgnoreCase ("hello")) {
  console.printf("first is equal to second. \n");
  system.exit(0);
}
Damion Samuels
Damion Samuels
7,624 Points
Damion Samuels
Damion Samuels
7,624 Points

if (firstExample.equals(secondExample)) { console.printf("first is equal to second"); }

Unsubscribed User
Unsubscribed User
7,386 Points
Unsubscribed User
Unsubscribed User
7,386 Points

I thank you for your time however, it still shows as incorrect according to the automated system. // I have imported a java.io.Console for you, it is named console. String firstExample = "hello"; String secondExample = "hello"; String thirdExample = "HELLO";

if (firstExample.equalsIgnoreCase(secondExample)) { console.printf("first is equal to second. \n"); system.exit(0); }

Ethan M
Ethan M
10,637 Points

system.exit(0) is not needed :)

Thomas Salai
Thomas Salai
4,964 Points
Thomas Salai
Thomas Salai
4,964 Points

What wrong with my code here.?

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample.equals(secondExample){
  console.printf("first is equal");
}

I got an error.

Bummer! There is a compiler error. Please click on preview to view your syntax errors!
Thomas Salai
Thomas Salai
4,964 Points
Thomas Salai
Thomas Salai
4,964 Points

I found the syntax error.. in if statement.. I forgot the end ")".