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Micah Dunson
34,368 PointsAnswer works in browser but not Treehouse challenge?
I don't know what the challenge is asking for ?
Challenge Task 3 of 3
In the "reviews" table, with the column "score", return the average of all movie's joint scores. Alias the aggregated column as "average_all_scores".
My Answer
SELECT MIN(score) AS minimum_score, MAX(score) AS maximum_score, AVG(score) AS average_all_scores FROM reviews;
My answer works fine in the browser however treehouse indicates it is wrong
Treehouse: Bummer! There's something wrong with your query, alias the AVG(score) AS min_score and SELECT from the 'reviews' table.
3 Answers
jcorum
71,830 PointsMicah, thanks. The problem is that you have sort of combined the queries for Tasks 2 and 3 together. But the editor wants each one done separately, and not combined with any other. So Task 3 would be:
SELECT AVG(score) AS average_all_scores FROM reviews;
Micah Dunson
34,368 PointsYou're absolutely right! I'm thinking too hard lol. Thanks
Nathan Williams
Python Web Development Techdegree Student 6,851 PointsFrom the hint you copied, I think the issue is that the result needs to be aliased as min_score, not minimum_score
jcorum
71,830 Pointsjcorum
71,830 PointsMicah, can you give us a link to the challenge. Your SQL does look OK, but it's not clear what the challenge is asking you to do, so I can't tell what it wants different.