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Start your free trialamna khalil
3,731 PointsArithmetic Calculator
using System; class math { static void Main() { var number=""; while (number != "QUIT") { Console.WriteLine("Please enter a number"); number=Console.ReadLine();
if(number.ToUpper()== "QUIT")
{
break;
}
else
{
try
{
int number1 = Int32.Parse(number);
Console.WriteLine("Please enter an operation");
var operation= Console.ReadLine();
Console.WriteLine("Please enter second number");
int number2= Int32.Parse(Console.ReadLine());
switch(operation)
{
case "+":
Console.WriteLine (number1 + number2);
break;
case "-":
Console.WriteLine (number1 - number2);
break;
case "*":
Console.WriteLine (number1 * number2);
break;
case "/":
Console.WriteLine (number1 / number2);
break;
}
}
catch(FormatException)
{
Console.WriteLine("Invalid input");
}
}
}
} } i wrote this done , how do i check the operation signs? i don't want to use if statements again and again. please tell me a better way to do it
3 Answers
Steven Parker
231,172 PointsUsing switch/case
was a good idea.
I think your use of the switch/case
statements is already better than chaining if
statements. And your program seems to work well. Is there some other question you have about it?
amna khalil
3,731 Pointsthe problem with this program is that when it asks to enter operation it does not check for invalid inputs, and it only checks for quit in the first question. is there a way to use that code again or do i need to write it again for the 2nd and 3rd input lines?
Steven Parker
231,172 PointsYou might put the part that reads input and checks it for "quit" in a separate function to make it easier to re-use. And checking for valid input will require a little bit of additional code.
amna khalil
3,731 Pointsthanx a lot