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Python Practice Creating and Using Functions in Python Practice Functions Use an External Function

taliarosen
taliarosen
2,492 Points

AssertionError

I'm getting an AssertionError on line 15 and I'm not sure what that means or what I should fix

using_a_function.py
"""
This is importing a function named `tweet` from a file
    that we unfortunately don't have access to change.

You use it like so:
>>> tweet("Hello this is my tweet")

If the function cannot connect to Twitter,
    the function will raise a `CommunicationError`
If the message is too long,
    the function will raise a `MessageTooLongError`
"""
MAX_ALLOWED = 42

from twitter import (
    tweet,
    MessageTooLongError,
    CommunicationError,
)


message = input("What would you like to tweet?  ")
# Your code here
if len(message) > MAX_ALLOWED:
    raise  MessageTooLongError
try:
    tweet(message)
    if len(message) > MAX_ALLOWED:
        raise  MessageTooLongError
except MessageTooLongError:
    print("Oh no! Your message was too long ({})".format(message))
except CommunicationError:
    print("An error occurred attempting to connect to Twitter. Please try again!")

1 Answer

Travis Alstrand
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Travis Alstrand
Treehouse Project Reviewer

Hey taliarosen !

The first error I encountered reads

AssertionError: False is not true : Make sure you catch the MessageTooLongError in a try except block

I would remove the if statement on lines 24&25, as we're already checking for this in our try block.

Then a new errors arrises reading

Bummer: AssertionError: 'max allowed is 42' not found in 'attempting to tweet: tfw you exclaim!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!\noh no! your message was too long (tfw you exclaim!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!)' : 

Make sure you output the message from the exception

So it seems it's not getting our message. But it's not asking for the message input variable that we gathered, it's saying The exception has additional messaging, so let's catch the exception and print it out. So we'll want to catch it with something like...

except MessageTooLongError as e:
    print("Oh no! Your message was too long ({})".format(e))```

This will print out the error message that comes along with this `MessageTooLongError`. I hope this makes sense!