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Start your free trialAllen Palacios
Full Stack JavaScript Techdegree Student 5,810 PointsCan I use &&?
I used && on my code and it worked. I'm wondering if that right or not?
// declare program variables
var num1;
var num2;
var message;
// announce the program
alert("Let's do some math!");
// collect numeric input
num1 = prompt("Please type a number");
num1 = parseFloat(num1);
num2 = prompt("Please type another number");
num2 = parseFloat(num2);
if( num2 === 0 ) {
alert( "Dude it's 0, you can't divide by 0. Reload and try again.");
}else if( isNaN(num1 && num2) ) {
alert( "At least one of these values is not a number. Reload and try again." );
} else {
// build an HTML message
message = "<h1>Math with the numbers " + num1 + " and " + num2 + "</h1>";
message += num1 + " + " + num2 + " = " + (num1 + num2);
message += "<br>";
message += num1 + " * " + num2 + " = " + (num1 * num2);
message += "<br>";
message += num1 + " / " + num2 + " = " + (num1 / num2);
message += "<br>";
message += num1 + " - " + num2 + " = " + (num1 - num2);
// write message to web page
document.write(message);
}
1 Answer
Robert Manolis
Treehouse Guest TeacherHi Allen, yes, you can definitely use the and operator, but I don't think you'll get the evaluation you're looking for with the way you have it set up. Rather than this: isNaN(num1 && num2)
, you most likely want this:
isNaN(num1) && isNaN(num2)
Hope that helps.