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Python Comparison Solution

Adam Kroner
Adam Kroner
1,460 Points
Posted by Adam Kroner
Adam Kroner
1,460 Points

Comparison Solution Help

I think this almost works but I do not understand why it always prints my else statement?

name = input("Please enter your name: ") number = input("Please enter a number: ")

number = int(number)

print("Hello{},\nthe number {}...".format(name, number))

if number % 3 == 0: print("is a Fizz number.") if number % 5 == 0: print("is a Buzz number.") if (number % 3) + (number % 5) == 0: print("is a FizzBuzz number.") else: print ("is neither a fizzy or a buzzy number.")

2 Answers

Steven Parker
Steven Parker
231,198 Points
Steven Parker
Steven Parker
231,198 Points

When posting code, you need to use Markdown formatting to preserve the appearance (particulary indentation); and without seeing the indentation it's impossible to predict how the code might behave.

But two issues visible as it is:

  • tests in a chain (after the first one) should use "elif" instead of "if"
  • a compound condition ("FizzBuzz") must be tested before the individual conditions
Adam Kroner
Adam Kroner
1,460 Points
Adam Kroner
Adam Kroner
1,460 Points

Heard sir I will try those, apologies on the construction in the question. It appeared alright when I copy and pasted but I did not check what it looked like on the forum.