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Aven Morgan
217 Pointsconfused
I am confused as to where I am going wrong can someone review and give a few pointers
// I have imported a java.io.Console for you, it is named console.
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample) {
console.printf ("first is equal to second");
}
if (firstExample.equalsIgnoreCase ("HELLO"))
if (firstExample == thirdExample) {
console.printf("first and third are the same ignoring case.");
}
2 Answers
Kevin Faust
15,353 PointsHey Aven,
The problem lies here:
if (firstExample.equalsIgnoreCase ("HELLO")) // needs { } here
if (firstExample == thirdExample) {
console.printf("first and third are the same ignoring case.");
}
You have an if statement that is invalid. If statements always need a opening and closing brace { } however as i noted above, you can see you dont have one. In if statements, it will check if the statement inside the parantheses is true and then it will run the code block, but as you can see you have no code block so the program is confused and will throw an error
Also we want to check if the first example is equal to the third example by ignoring the case. You are comparing the firstExample to the thirdExample twice. We just need one if statement to do this. It should look like this:
if (firstExample.equalsIgnoreCase(thirdExample)) {
console.printf("first and third are the same ignoring case");
}
it says "take the firstExample ("hello") and, ignoring cases, check if it equals the thirdExample ("HELLO")"
I hope that helped and you have a better understanding
If you have any other questions let me know! Dont forget to mark as best answer so others with the same question can see
Happy coding and all the best,
Kevin
Aven Morgan
217 PointsThank you Kevin it helped out a lot.