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Python

Creating doubles

I am trying to use the index in self with range, I was sure that would work, but I need help

hands.py
from dice import D6


class Hand(list):
    def __init__(self, size=0, die_class=None, *args, **kwargs):
        if not die_class:
            raise ValueError("You must provide a die class")
        super().__init__()

        for _ in range(size):
            self.append(die_class())
        self.sort()

    def _by_value(self, value):
        dice = []
        for die in self:
            if die == value:
                dice.append(die)
        return dice


class CapitalismHand(Hand):
    def __init__(self, *args, **kwargs):
        super().__init__(size=2, die_class=D6, *args, **kwargs)

    @property
    def doubles(self):
        for x in range(6)
            if self[x] == self[x]
        return True

    @property
    def ones(self):
        return self._by_value(1)

    @property
    def twos(self):
        return self._by_value(2)

    @property
    def threes(self):
        return self._by_value(3)

    @property
    def fours(self):
        return self._by_value(4)

    @property
    def fives(self):
        return self._by_value(5)

    @property
    def sixes(self):
        return self._by_value(6)

    @property
    def _sets(self):
        return {
            1: len(self.ones),
            2: len(self.twos),
            3: len(self.threes),
            4: len(self.fours),
            5: len(self.fives),
            6: len(self.sixes)
        }

1 Answer

Jeff Wilton
Jeff Wilton
16,646 Points

Since you know you have exactly two dice, you can just access them directly like this:

@property
def doubles(self):
    return self[0] == self[1]