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Start your free trialjdee
6,655 PointsDebugging
from_str() below seems to work in workspaces, but it is not accepted. Por que no?!
class Letter:
def __init__(self, pattern=None):
self.pattern = pattern
def __iter__(self):
yield from self.pattern
def __str__(self):
output = []
for blip in self:
if blip == '.':
output.append('dot')
else:
output.append('dash')
return '-'.join(output)
@classmethod
def from_string(cls, item):
output = []
for s in item.split("-"):
if s == "dash":
output.append("_")
else:
output.append(".")
return output
class S(Letter):
def __init__(self):
pattern = ['.', '.', '.']
super().__init__(pattern)
3 Answers
KRIS NIKOLAISEN
54,971 PointsThe instructions include:
creates an instance with the correct pattern
This is shown in the previous video @ 2:20
For the code above you would return cls(output)
jdee
6,655 PointsThanks. So I get that I forgot the cls(output) part. But it still doesn't work for me in workspaces (even though the Challenge accepted that solution). When I run the accepted solution, i get: "type error: init() takes 1 positional args but 2 was given".
I am likely trying to execute the code wrong. I'm doing the below, which (I think) when it calls from_string(), it creates an instance of Letter, and Letter requires 1 arg (a pattern object, right?), but how am I giving it 2?
cls = S.from_string("dash-dot")
print(cls)
How should it be called?