Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialNathan Magyar
11,332 PointsDidn't find an URL for your view [Solved]
I am trying to create a URL for my class-based view, which has a get
method, returns an HttpResponse
, and is instantiated using the as_view()
method in the URL pattern list. What am I missing that causes the error "Didn't find an URL for your view"?
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'/', views.WelcomeView.as_view(), name="welcome")
]
from django.views.generic import View
from django.http import HttpResponse
class WelcomeView(View):
def get(self, request):
return HttpResponse("Blahhhh")
This is the prompt for this challenge: Alright, last step. Import HttpResponse from django.http. Then change your get method to return an HttpRepsonse with whatever string you want in the response. Also, add a URL to myproject/urls.py for your WelcomeView. The route should just be /.
1 Answer
Nathan Magyar
11,332 Points[SOLVED]
The error was in my route. To create a URL that's just '/', the necessary regex is r'^$'
because the /
gets added automatically.