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Python Django Class-based Views Classy Views Basic View

Nathan Magyar
Nathan Magyar
11,332 Points

Didn't find an URL for your view [Solved]

I am trying to create a URL for my class-based view, which has a get method, returns an HttpResponse, and is instantiated using the as_view() method in the URL pattern list. What am I missing that causes the error "Didn't find an URL for your view"?

myproject/urls.py
from django.conf.urls import url, include

from . import views

urlpatterns = [
    url(r'/', views.WelcomeView.as_view(), name="welcome")
]
myproject/views.py
from django.views.generic import View
from django.http import HttpResponse

class WelcomeView(View):
    def get(self, request):
        return HttpResponse("Blahhhh")

This is the prompt for this challenge: Alright, last step. Import HttpResponse from django.http. Then change your get method to return an HttpRepsonse with whatever string you want in the response. Also, add a URL to myproject/urls.py for your WelcomeView. The route should just be /.

1 Answer

Nathan Magyar
Nathan Magyar
11,332 Points

[SOLVED]

The error was in my route. To create a URL that's just '/', the necessary regex is r'^$' because the / gets added automatically.