Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript Build a Two-Dimensional Array

Posted by Yuting Le
.a{fill-rule:evenodd;}techdegree seal-36
Yuting Le
Full Stack JavaScript Techdegree Graduate 20,125 Points

Does these two codes work the same in here?

The code in teacher's notes:

for (let i=0; i<suites.length; i++) {
   for (let j=0; j<ranks.length; j++) {
     let card = [];
     card.push(ranks[j], suites[i]);
     deck.push(card);
   }
  }

My code:

for (let i = 0; i < suites.length; i ++){
    for (let j = 0; j < ranks.length; j ++){
      let card = [suites[i], ranks[j]];
      deck.push(card);
    }
  }

1 Answer

Steven Parker
Steven Parker
231,261 Points
Steven Parker
Steven Parker
231,261 Points

It looks like you have the item order reversed, but otherwise this would be an improvement on the example by saving a step!

But you can save yet another step and also eliminate the "card" variable completely:

      deck.push([ranks[j], suites[i]]);