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OMAR ANDERSON
Courses Plus Student 68 Pointsensure you put %s
need help
String firstName ="Craig";
console.readLine("firstName");
String lastName ="Craig";
console.readLine("lastName");
console.printf("First name,Craig:",firstName);
3 Answers
Kjetil Lorentzen
13,360 PointsHi Omar, In order to use printf() and write formatted output you need to use %s for attaching string variables to the output.
Check out: https://www.cs.colostate.edu/~cs160/.Spring16/resources/Java_printf_method_quick_reference.pdf or https://docs.oracle.com/javase/tutorial/java/data/numberformat.html.
For this particular challenge
String firstName = console.readLine();
String lastName = console.readLine();
console.printf("First name: %s", firstName);
console.printf("Last name: %s",lastName);
OMAR ANDERSON
Courses Plus Student 68 Pointsthank you for responding, but i did all that and im still getting this error "Bummer! Did you forget to pass the firstName parameter to the printf function?"
OMAR ANDERSON
Courses Plus Student 68 PointsString firstName ="Omar"; console.readLine(firstName);
String lastName ="brown"; console.readLine(lastName); console.printf("First name:%s\n" ,firstName); console.printf("Last name: %s", lastName);