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Python

Posted by Nathan Garcia
Nathan Garcia
9,098 Points

Harder Time Machine - Formatting Output

I feel like I'm so close to solving this. My output is correct but not matching the format of the example.

Output should be: datetime(2015, 10, 21, 16, 34) My output is: 2015-10-21 16:24:00

# Write a function named time_machine that takes an integer and a string of "minutes", "hours", "days", or "years".
# This describes a timedelta. Return a datetime that is the timedelta's duration from the starter datetime.
import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(my_int, my_str):
    starter = datetime.datetime(2015, 10, 21, 16, 29)
    if my_str.upper() == 'MINUTES':
        return starter - datetime.timedelta(minutes=my_int)
    if my_str.upper() == 'HOURS':
        return starter - datetime.timedelta(hours=my_int)
    if my_str.upper() == 'DAYS':
        return starter - datetime.timedelta(days=my_int)
    if my_str.upper() == 'YEARS':
        my_int = my_int * 365
        return starter - datetime.timedelta(days=my_int)
Nathan Garcia
Nathan Garcia
9,098 Points

I tried returning starter.strftime('%Y, %m, %d, %H, %M') but that didn't fix it.

1 Answer

Nathan Garcia
Nathan Garcia
9,098 Points

Crap, I figured it out. I needed to Add not Subtract.