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Python Introducing Lists Build an Application Multidimensional Musical Groups

walter fernandez
walter fernandez
4,992 Points
Posted by walter fernandez
walter fernandez
4,992 Points

hello i have a problem in my code

I am getting the right answer when, but for some reason, that is not the answer that they expect.

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]

# answer Challenge 2
for group in musical_groups: # loop through the list of lists
        if len(group) == 3: #only print out the groups with 3 members
            print('. '.join(group) + "\n") # print each member joined by a seperator

1 Answer

Robin Goyal
Robin Goyal
4,582 Points
Robin Goyal
Robin Goyal
4,582 Points

You have a period (.) as the separator instead of a comma (,). The other thing is that print by default adds the newline character by default so you don't need to include the "\n" character. 

print(", ".join(group))